Top 32 Latest ASME B16.5 Practice Questions and Answers – Closed Book
Are you looking for a reliable source of ASME B16.5 practice questions and answers? Do you want to improve your understanding of pipe flanges, flanged fittings, pressure-temperature ratings, bolting requirements, dimensions, markings, and hydrostatic testing requirements?
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UpWeld provides a free ASME B16.5 closed-book practice test featuring 32 carefully prepared multiple-choice questions with correct answers and clear explanations. These questions are designed to help inspectors, engineers, technicians, welding professionals, and certification candidates strengthen their knowledge of ASME B16.5 requirements.
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Improve your exam preparation with UpWeld’s ASME B16.5 practice tests, study materials, and exam question packages. Our questions cover important topics such as:
- Scope and pressure classes
- Flange and flanged-fitting requirements
- Pressure-temperature ratings
- Flange facing finishes
- Bolting materials and strength requirements
- Product markings
- Hydrostatic test pressures
- Minimum wall thickness
- Dimensional requirements
- Local areas of subminimum thickness
Each practice question includes four answer options, the correct answer, and a detailed explanation to help you understand the applicable requirement.
Latest ASME B16.5 Questions and Answers
Our ASME B16.5 questions and answers are reviewed for technical accuracy and presented in an easy-to-understand format. The practice test can help you identify weak areas, improve code-book familiarity, and develop greater confidence before an examination or technical interview.
The ASME B16.5 study material is suitable for:
- Piping inspectors
- Welding inspectors
- Quality control inspectors
- Mechanical engineers
- Piping engineers
- Plant inspection personnel
- Maintenance professionals
- Certification candidates
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Latest ASME B16.5 Practice Questions and Answers
Q1. ASME B16.5 does not cover which of the following?
A. Class 150 pipe flanges
B. Class 300 flanged fittings
C. Butt-welding pipe caps
D. NPS 24 Class 600 flanges
Correct Answer: C. Butt-welding pipe caps
Explanation: ASME B16.5 covers pipe flanges and flanged fittings within the specified pressure classes and nominal pipe sizes. Factory-made butt-welding pipe caps are covered by ASME B16.9, not ASME B16.5.
Q2. What hydrostatic test pressure may normally be applied to flanged joints and flanged fittings under ASME B16.5?
A. The 100°F pressure rating without any multiplier
B. 1.5 times the 100°F pressure rating, rounded upward to the next 25 psi
C. 1.25 times the pressure rating at operating temperature
D. Twice the 100°F pressure rating
Correct Answer: B. 1.5 times the 100°F pressure rating, rounded upward to the next 25 psi
Explanation: ASME B16.5 permits a system hydrostatic test pressure equal to 1.5 times the pressure rating at 100°F. The calculated pressure is rounded upward to the next 25-psi increment. Testing above this pressure is the responsibility of the user and must comply with the applicable construction code.
Q3. Under ASME B16.5, high-strength bolting has allowable stresses not less than those for:
A. ASTM A307 Grade B
B. ASTM A193 Grade B5
C. ASTM A320 Grade L7
D. ASTM A193 Grade B7
Correct Answer: D. ASTM A193 Grade B7
Explanation: High-strength bolting is bolting having allowable stresses not less than those specified for ASTM A193 Grade B7. Bolting materials having equivalent or greater strength may also be suitable.
Q4. Which pressure classes are covered by ASME B16.5?
A. Class 150, 300, 400, 600, 900, 1500, and 2500
B. Class 125, 150, 300, 600, 900, and 1500
C. Class 150, 300, 450, 600, 900, and 1500
D. Class 150, 300, 400, 600, 700, 900, and 1000
Correct Answer: A. Class 150, 300, 400, 600, 900, 1500, and 2500
Explanation: ASME B16.5 covers pipe flanges and flanged fittings in Classes 150, 300, 400, 600, 900, 1500, and 2500.
Q5. What is the required surface roughness range for a standard serrated raised-face flange finish?
A. 63 to 125 microinches Ra
B. 125 to 250 microinches Ra
C. 250 to 500 microinches Ra
D. 500 to 1,000 microinches Ra
Correct Answer: B. 125 to 250 microinches Ra
Explanation: Raised-face and large male-and-female gasket-contact surfaces normally require a resultant surface roughness between 125 and 250 microinches arithmetic average, or Ra.
Q6. Flanged assemblies using low-strength carbon steel bolting should normally be limited to which service-temperature range?
A. −50°F to 500°F
B. −20°F to 650°F
C. −20°F to 400°F
D. 0°F to 750°F
Correct Answer: C. −20°F to 400°F
Explanation: Flanged assemblies using low-strength carbon steel bolting should not normally be used above 400°F or below −20°F. Low-strength bolting may not provide adequate joint performance outside this temperature range.
Q7. Low-strength bolting is defined as bolting having no more than:
A. 30 ksi specified minimum yield strength
B. 30 ksi specified minimum tensile strength
C. 60 ksi specified minimum yield strength
D. 100 ksi specified minimum tensile strength
Correct Answer: A. 30 ksi specified minimum yield strength
Explanation: Low-strength bolting has a specified minimum yield strength not exceeding 30 ksi. Its use is generally restricted to Class 150 and Class 300 flanged joints.
Q8. What is the maximum permitted roughness of ring-joint gasket-groove sidewall surfaces?
A. 32 microinches Ra
B. 50 microinches Ra
C. 125 microinches Ra
D. 63 microinches Ra
Correct Answer: D. 63 microinches Ra
Explanation: Ring-joint gasket-groove sidewall surfaces must not exceed 63 microinches Ra. The surfaces must also be free from harmful ridges, tool marks, or chatter that could affect sealing.
Q9. Which of the following information is required to be marked on flanges and flanged fittings?
A. Maximum operating temperature selected by the owner
B. Actual system working pressure
C. Material specification and grade identification
D. System hydrostatic test pressure
Correct Answer: C. Material specification and grade identification
Explanation: Required markings normally include the manufacturer’s identification, material designation, pressure class, and nominal size. Actual system working pressure and hydrostatic test pressure are not standard flange product markings.
Q10. Above what temperature may Class 150 flanged joints develop leakage unless special precautions are taken regarding external loads and thermal gradients?
A. 300°F
B. 400°F
C. 600°F
D. 750°F
Correct Answer: B. 400°F
Explanation: Class 150 flanged joints may develop leakage at temperatures above 400°F unless special consideration is given to external loads, thermal gradients, and differential thermal expansion.
Q11. What are the three fundamental components of a bolted flanged joint?
A. Flanges, gasket, and bolting
B. Flanges, welds, and gaskets
C. Flanges, bolts, and pipe threads
D. Flanges, nuts, and weld metal
Correct Answer: A. Flanges, gasket, and bolting
Explanation: A bolted flanged joint consists of two mating flanges, a gasket or sealing element, and bolting. Proper selection and assembly of all three components are necessary for a leak-tight joint.
Q12. Class 600 flanged joints may develop leakage unless special consideration is given to thermal gradients and external loads at temperatures above:
A. 400°F
B. 600°F
C. 950°F
D. 750°F
Correct Answer: D. 750°F
Explanation: Flanged joints other than Class 150 may require special consideration when used above 750°F. External loads, thermal gradients, and differential expansion can reduce joint tightness.
Q13. A Class 400 flanged fitting has a pressure rating of 800 psig at 100°F. At what minimum hydrostatic shell-test pressure must the fitting be tested?
A. 1,000 psig
B. 1,125 psig
C. 1,200 psig
D. 1,225 psig
Correct Answer: C. 1,200 psig
Explanation: The required hydrostatic shell-test pressure is calculated as follows:
Hydrostatic test pressure = 1.5 × pressure rating at 100°F
Hydrostatic test pressure = 1.5 × 800 psig
Hydrostatic test pressure = 1,200 psig
Therefore, the minimum hydrostatic shell-test pressure is 1,200 psig.
Q14. What is the maximum permitted temperature of the test fluid during hydrostatic testing of a flanged fitting?
A. 125°F
B. 100°F
C. 150°F
D. 200°F
Correct Answer: A. 125°F
Explanation: The temperature of the test fluid during hydrostatic testing must not exceed 125°F. This limitation supports consistent testing conditions and personnel safety.
Q15. What is the minimum hydrostatic shell-test duration for an NPS 12 flanged fitting?
A. 60 seconds
B. 90 seconds
C. 120 seconds
D. 180 seconds
Correct Answer: D. 180 seconds
Explanation: Flanged fittings NPS 10 and larger must be subjected to the required hydrostatic shell-test pressure for a minimum duration of 180 seconds or 3 minutes.
Q16. For an NPS 14 raised-face flange, what is the maximum depth and maximum radial projection of an isolated imperfection extending below the bottom of the serrations?
A. 0.018 in.
B. 0.18 in.
C. 0.25 in.
D. 0.31 in.
Correct Answer: B. 0.18 in.
Explanation: For an NPS 14 gasket-contact surface, the maximum permitted depth and radial projection of an isolated imperfection extending below the serrations is 0.18 in.
Q17. What is the minimum flange thickness for an NPS 24 Class 600 flange?
A. 4.00 in.
B. 3.00 in.
C. 4.50 in.
D. 6.00 in.
Correct Answer: A. 4.00 in.
Explanation: The ASME B16.5 dimensional table for Class 600 flanges specifies a minimum flange thickness of 4.00 in. for an NPS 24 flange.
Q18. What is the pressure rating at 100°F of a Class 150 flange manufactured from ASTM A182 Grade F2 material?
A. 170 psig
B. 275 psig
C. 290 psig
D. 300 psig
Correct Answer: C. 290 psig
Explanation: ASTM A182 Grade F2 belongs to Material Group 1.7. The ASME B16.5 pressure-temperature rating table gives a Class 150 rating of 290 psig at temperatures from −20°F through 100°F.
Q19. ASTM A182 Grade F347, excluding the high-carbon F347H grade, must not be used above what temperature?
A. 900°F
B. 1,000°F
C. 1,200°F
D. 1,500°F
Correct Answer: B. 1,000°F
Explanation: ASTM A182 Grade F347 must not be used above 1,000°F. Grade F347H may be permitted at higher temperatures when its chemical composition and heat-treatment requirements are satisfied.
Q20. What is the minimum wall thickness of an NPS 16 Class 900 flanged fitting?
A. 0.91 in.
B. 1.25 in.
C. 2.60 in.
D. 1.56 in.
Correct Answer: D. 1.56 in.
Explanation: The applicable ASME B16.5 fitting-wall-thickness table lists a minimum wall thickness of 1.56 in. for an NPS 16 Class 900 flanged fitting.
Q21. What is the approximate rated working pressure for a Class 400 material having a stress value of 16,200 psi?
A. 740 psig
B. 800 psig
C. 1,000 psig
D. 1,500 psig
Correct Answer: A. 740 psig
Explanation: For Class 300 and higher ratings, the pressure is calculated as follows:
Rated pressure = Material stress value ÷ 8,750 × pressure class
Rated pressure = 16,200 ÷ 8,750 × 400
Rated pressure = 740.6 psig
Therefore, the approximate rated working pressure is 740 psig, provided it does not exceed the applicable ceiling pressure.
Q22. What is the minimum wall thickness of an NPS 5 Class 1500 flanged fitting?
A. 0.091 in.
B. 1.15 in.
C. 0.91 in.
D. 1.50 in.
Correct Answer: C. 0.91 in.
Explanation: The applicable ASME B16.5 fitting-wall-thickness table lists a minimum wall thickness of 0.91 in. for an NPS 5 Class 1500 flanged fitting.
Q23. A Class 300 flange made from Material Group 1.10 has a 100°F pressure rating of 750 psig. What system hydrostatic test pressure for the system?
A. 1,000 psig
B. 1,125 psig
C. 750 psig
D. 450 psig
Correct Answer: B. 1,125 psig
Explanation: The permitted system hydrostatic test pressure is calculated as follows:
Hydrostatic test pressure = 1.5 × pressure rating at 100°F
Hydrostatic test pressure = 1.5 × 750 psig
Hydrostatic test pressure = 1,125 psig
Therefore, the permitted system hydrostatic test pressure is 1,125 psig.
Q24. An NPS 8 Class 400 flanged fitting has a tabulated minimum wall thickness of 0.56 in. A localized area is measured at 0.400 in. Is the local thinning acceptable?
A. Yes, because any localized thinning is acceptable
B. Yes, because 0.400 in. exceeds 50% of the minimum thickness
C. It cannot be evaluated without knowing the pressure
D. No, because it is less than 75% of the minimum thickness
Correct Answer: D. No, because it is less than 75% of the minimum thickness
Explanation: The minimum permitted thickness in a qualifying localized area is 75% of the tabulated minimum wall thickness.
Minimum acceptable thickness = 0.75 × 0.56 in.
Minimum acceptable thickness = 0.420 in.
The measured thickness is 0.400 in., which is less than 0.420 in. Therefore, the localized thinning is not acceptable.
Q25. For the NPS 8 Class 400 fitting described in Question 24, what is the maximum circular area that may enclose a region of subminimum thickness?
A. Approximately 0.431 square inches
B. Approximately 0.740 square inches
C. Approximately 1.85 square inches
D. Approximately 2.75 square inches
Correct Answer: A. Approximately 0.431 square inches
Explanation: The maximum permitted enclosure-circle diameter is calculated as follows:
Circle diameter = 0.35 × square root of inside diameter × minimum wall thickness
Circle diameter = 0.35 × square root of 8.00 × 0.56
Circle diameter = approximately 0.741 in.
The circular area is then calculated as follows:
Circular area = 3.1416 × diameter × diameter ÷ 4
Circular area = 3.1416 × 0.741 × 0.741 ÷ 4
Circular area = approximately 0.431 square inches
Therefore, the maximum circular area is approximately 0.431 square inches.
Q26. For the NPS 8 Class 400 fitting described in Question 24, what minimum edge-to-edge separation is required between two enclosure circles containing subminimum wall thickness?
A. More than 2.70 in.
B. More than 3.00 in.
C. More than 3.70 in.
D. More than 8.00 in.
Correct Answer: C. More than 3.70 in.
Explanation: The minimum required separation is calculated as follows:
Minimum separation = 1.75 × square root of inside diameter × minimum wall thickness
Minimum separation = 1.75 × square root of 8.00 × 0.56
Minimum separation = approximately 3.70 in.
Therefore, the edges of the two enclosure circles must be separated by more than 3.70 in.
Q27. A Class 600 flange manufactured from Material Group 3.5 has a 100°F pressure rating of 1,500 psig. What system hydrostatic test pressure is permitted?
A. 1,500 psig
B. 2,250 psig
C. 1,000 psig
D. 3,750 psig
Correct Answer: B. 2,250 psig
Explanation: The system hydrostatic test pressure is calculated as follows:
Hydrostatic test pressure = 1.5 × pressure rating at 100°F
Hydrostatic test pressure = 1.5 × 1,500 psig
Hydrostatic test pressure = 2,250 psig
Therefore, the permitted system hydrostatic test pressure is 2,250 psig.
Q28. An NPS 12 Class 900 flanged fitting has a tabulated minimum wall thickness of 1.25 in. What is the minimum acceptable measured thickness within a qualifying local area?
A. 1.750 in.
B. 1.250 in.
C. 0.945 in.
D. 0.9375 in.
Correct Answer: D. 0.9375 in.
Explanation: A qualifying localized area must not be thinner than 75% of the tabulated minimum wall thickness.
Minimum acceptable thickness = 0.75 × 1.25 in.
Minimum acceptable thickness = 0.9375 in.
Therefore, the minimum acceptable measured thickness is 0.9375 in.
Q29. For the NPS 12 Class 900 fitting described in Question 28, what is the approximate maximum circular area that may enclose subminimum thickness?
A. 1.33 square inches
B. 1.85 square inches
C. 2.75 square inches
D. 0.431 square inches
Correct Answer: A. 1.33 square inches
Explanation: The maximum enclosure-circle diameter is calculated as follows:
Circle diameter = 0.35 × square root of inside diameter × minimum wall thickness
Circle diameter = 0.35 × square root of 11.12 × 1.25
Circle diameter = approximately 1.30 in.
The circular area is calculated as follows:
Circular area = 3.1416 × diameter × diameter ÷ 4
Circular area = 3.1416 × 1.30 × 1.30 ÷ 4
Circular area = approximately 1.33 square inches
Therefore, the maximum circular area is approximately 1.33 square inches.
Q30. For the NPS 12 Class 900 fitting described in Question 28, what minimum edge-to-edge distance is required between two enclosure circles containing subminimum wall thickness?
A. More than 3.00 in.
B. More than 4.70 in.
C. More than 6.52 in.
D. More than 8.00 in.
Correct Answer: C. More than 6.52 in.
Explanation: The minimum required edge-to-edge separation is calculated as follows:
Minimum separation = 1.75 × square root of inside diameter × minimum wall thickness
Minimum separation = 1.75 × square root of 11.12 × 1.25
Minimum separation = approximately 6.52 in.
Therefore, the edges of the two enclosure circles must be separated by more than 6.52 in.
Q31. Using the ASME B16.5 fitting-wall calculation, what is the calculated wall thickness before the additional tabular allowance is applied for an NPS 14 Class 900 flanged fitting having an inside diameter of 12.25 in.?
A. 0.830 in.
B. 1.28 in.
C. 1.38 in.
D. 1.56 in.
Correct Answer: B. 1.28 in.
Explanation: The fitting-wall thickness is calculated using the class designation, inside diameter, and fitting stress value.
Calculated thickness = 1.5 × class designation × inside diameter ÷ the result of twice the fitting stress value minus 1.2 times the class designation
Calculated thickness = 1.5 × 900 × 12.25 ÷ the result of 2 × 7,000 minus 1.2 × 900
Calculated thickness = 16,537.5 ÷ 12,920
Calculated thickness = approximately 1.28 in.
Therefore, the calculated wall thickness before the additional tabular allowance is approximately 1.28 in. The tabulated minimum wall thickness is higher because an additional manufacturing allowance is included.
Q32. A Class 600 flanged fitting operates at 650°F. The applicable stress value is 17,400 psi. What is its maximum permitted rated working pressure after applying the table ceiling pressure?
A. 2,000 psig
B. 1,193 psig
C. 1,500 psig
D. 1,175 psig
Correct Answer: D. 1,175 psig
Explanation: The calculated rated pressure is determined as follows:
Calculated rated pressure = Material stress value ÷ 8,750 × pressure class
Calculated rated pressure = 17,400 ÷ 8,750 × 600
Calculated rated pressure = approximately 1,193 psig
However, the calculated pressure must not exceed the applicable ceiling pressure. At 650°F, the Class 600 ceiling pressure is 1,175 psig.
Therefore, the maximum permitted rated working pressure is 1,175 psig.
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